First Tabletop
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Mechanical Energy problem, please help!!?
A 4.50 g bullet is fired horizontally at two blocks at rest on a frictionless tabletop. The bullet passes through the first block, with mass 1.20 kg, and embeds itself in the second, with mass 1.80 kg. Speeds of 0.630 m/s and 1.40 m/s, respectively, are thereby given to the blocks. (Note: You may neglect the mass removed from the first block by the bullet.)
I already got these two:
The speed of the bullet after emerging from first block = 564.83 m/s.
The bullet's original speed = 434.48 m/s.
(a) How much mechanical energy was dispelled into the environment during the bullet's collision with the first block?
wrong check mark J
(b) How much mechanical energy was dispelled into the environment during the bullet's collision with the second block?
Please show me how you got the answer for a & b. Thank you!!
Kinetic energy = m v ² / 2
v0 = Initial speed of bullet
v1 = Speed of bullet emerging from block 1
b1,b2 = Speed of blocks 1 & 2
m, m1, m2 = Masses of bullet, block 1 and block 2 respectively
From conservation of energy
a) 0.5 (m v0 ² - m v1 ² - m1 b1 ²)
b) 0.5 (m v1 ² - (m + m2) b2 ²)